SOLUTION: write the expression as a single logarithm log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) so far i have been able to factor the equations to get log((x+3)(x-1))/((x+2)(x-2))-log(

Question 768302: write the expression as a single logarithm
log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2)
so far i have been able to factor the equations to get
log((x+3)(x-1))/((x+2)(x-2))-log((x+1)(x+6))/(x+2)

if possible show steps.
thank you

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
write the expression as a single logarithm
log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2)
log((x^2+2x-3)/(x^2-4)/(x^2+7x+6)/(x+2))
log(((x+3)(x-1)/(x+2)(x-2))/((x+6)(x+1)/(x+2)))
log(((x+3)(x-1)/(x+2)(x-2))*((x+2)/(x+6)(x+1)))
(x+2) cancels out

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