SOLUTION: if 2^x+y = 6^y. then find the value of x/y
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Question 763938: if 2^x+y = 6^y. then find the value of x/y
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
You really need to use parentheses to group things together. I have to assume that the 
in the LHS is part of the exponent on 2 since the problem isn't solvable algebraically otherwise. But for the sake of clear understanding you should have posted
2^(x+y) = 6^y
Going on that presumption
\ =\ y\log_b(3))
Note: The base you choose for the logarithm doesn't matter -- }{\log_{b_1}\left(x_2\right)}\ =\ \frac{\log_{b_2}\left(x_1\right)}{\log_{b_2}\left(x_2\right)}\ \forall b_i\ \in\ \mathbb{R}\ >\ 0)
}{\log_b(2)})
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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