SOLUTION: how do i solve (1/36)^x-1 =1296^2x

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Question 755750: how do i solve (1/36)^x-1 =1296^2x
Found 2 solutions by Edwin McCravy, MathLover1:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!

x-2 = 12962x

Write 1296 as 362
Write  as 36-1

(36-1)x-2 = (362)2x

Remove the parentheses by multiplying the exponents:

36-x+2 = 364x

Since the base 36 is positive and not 1, we may drop the
36's and set their exponents equal to each other:

-x+2 = 4x
 -5x = -2
   x = 
   x = 

Edwin
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

.......write as and as
.........since we have

..since bases same, exponents are same too; so, we have

....solve for







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