SOLUTION: e^x=2e^(x/2)+35

Question 754890: e^x=2e^(x/2)+35
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
e^x=2e^(x/2)+35
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Quadratic in e^(x/2):
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(e^(x/2))^2 -2e^(x/2) - 35 = 0
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Factor:
(e^(x/2)-7)(e^(x/2)+5) = 0
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Positive solution:
e^(x/2) = 7
(x/2) = ln(7)
x = 2*ln(7)
x = ln(49)
==================
Cheers,
Stan H.
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