SOLUTION: Log(base2) x^2/3 - 5x^1/3 + 6= 0,
Algebra.Com
Question 752634: Log(base2) x^2/3 - 5x^1/3 + 6= 0,
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2/3 - 5x^1/3 + 6= 0
---------
That is a quadratic equation with variable x^(1/3)
===========================
Factor:
(x^(1/3)-6)(x^(1/3)+1) = 0
-----
x^(1/3) = 6 or x^(1/3) = -1
---
x = cbrt(6) or x = -1
==========================
Cheers,
Stan H.
==================
RELATED QUESTIONS
please kindly assist me..
log base2 (x+1)= log base2 x + log base2... (answered by josgarithmetic)
what is log base6 4 + log base 6 (x+2) = 1?
what is log base2 (x+6)- log base2 (x) = 3?
(answered by nerdybill)
log(base2)8 + 2log(base2)x =... (answered by lwsshak3)
i have no idea to solve thiese type of question, if will be great if u can help me,... (answered by Nate)
Solve for x:
a) (log base2 x)^2-(logbase2 x^2)=0
b) log base2(logbasex 64)=1
c) log... (answered by stanbon)
how to express as a logarithm of a single number:
1. 7 log base2 x- 1/3 log base2 y
(answered by stanbon)
How do I solve the following for x?
log(base2)9 / log(base2)3 = log(base2)2x
I tried... (answered by lwsshak3)
log base2 (3)+log base 2 (x)= log base 2... (answered by jsmallt9)