SOLUTION: lne^(x^2+3x-4)=ln5
Algebra.Com
Question 750964: lne^(x^2+3x-4)=ln5
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
lne^(x^2+3x-4)=ln5
log of base raised to exponent=exponent
(x^2+3x-4)=ln5
(x^2+3x-4)=ln(5)≈1.6094
x^2+3x-4-1.6094=0
x^2+3x-5.6094=0
use quadratic formula to solve for x
a=1, b=3, c=5.6094
x≈1.3035
or
x≈-4.3035
RELATED QUESTIONS
lne^(x^2+4) (answered by ewatrrr)
solve... (answered by srinivas.g)
How do you solve for x in:... (answered by richard1234)
ln(x+4)-ln (2x+1)= ln5
(answered by dabanfield)
(ln5^-5)(ln(2/6^(4)))^-5 (answered by stanbon)
write as a single logarithm:
2lne + lne^2+lne^4... (answered by stanbon)
solve lne^5 =... (answered by stanbon)
If y=5^(x^3-2), then dy/dx=
(A) (x^3-2)5^(x^3-2)
(B) 3x^2(ln5)5^(x^3-2)
(C)... (answered by jim_thompson5910)
If y=5^(x^3-2), then dy/dx=
(A) (x^3-2)5^(x^3-2)
(B) 3x^2(ln5)5^(x^3-2)
(C)... (answered by jim_thompson5910)