SOLUTION: How to write these equations in logarithmic form?
49=(1/7)^-2
a=b^c
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Question 749444: How to write these equations in logarithmic form?
49=(1/7)^-2
a=b^c
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
How to write these equations in logarithmic form?
-----
Logs are exponents.
The base is what's raised to the exponent
49=(1/7)^-2
---------
a=b^c
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