SOLUTION: I need help with:
1) log (x² - 1) = log 3
2) log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
3) log base x + 1 (x² - x) = 2
Please, help me!
Algebra.Com
Question 745091: I need help with:
1) log (x² - 1) = log 3
2) log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
3) log base x + 1 (x² - x) = 2
Please, help me!
Answer by savvyhush23(50) (Show Source): You can put this solution on YOUR website!
Just wanna ask if you're asking the value of x here?
Anyway,
a) log (x² - 1) = log 3, you can eliminate the log
(x² - 1) = 3
x = 2
b)log base 2 (x + 3) + log base 2 (x - 3) = log base 2 7
log base 2[(x + 3)(x - 3)]= log base 2 7
(x + 3)(x - 3) = 7
x² - 9 = 7
x = 4
c)log base x + 1 (x² - x) = 2
Note:
log base a (Answer) = Exponent
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