SOLUTION: For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?

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Question 744933: For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?
Answer by lwsshak3(11628)   (Show Source): You can put this solution on YOUR website!
For the functions ƒ(x) = log_6(x) and g(x)=log_1/4(x), for what values of x is g(x) > ƒ(x)?


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At x=1, g(x)=f(x)
At x<1, g(x)>f(x)
Between (0 and 1), f becomes more negative as x becomes more negative; whereas, g becomes more positive as x becomes more negative.

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