SOLUTION: log[2](16^(4x))=6
Algebra.Com
Question 744338: log[2](16^(4x))=6
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log[2](16^(4x))=6
-----
4x*log2(16) = 6
----
4x*log2(2^4) = 6
---
4x*4*1 = 6
x = 6/16
x = 3/8
=============
Cheers,
Stan H.
=============
RELATED QUESTIONS
Solve the equation {{{log(16,(x))+log(8,(x))+log(4,(x))+log(2,(x))=6}}} (answered by jim_thompson5910)
help me solve
Simply the following expressions.
0.5 log 36 + 0.25 log 16 + 2 log 6
(answered by Ademola,greenestamps)
What is the domain of... (answered by Fombitz)
[(x^2)-4x+7]log 5 + log 16 = 4
I need to know x.
(answered by Alan3354)
log2=log(6+4x)+log(3x+6) (answered by stanbon)
Solve log base 6 of x + log base 6 of... (answered by Gogonati)
Write as a single log:
1/3 log(8c^6)+2 log (3a)-1/2 log 16 I think the answer is... (answered by stanbon)
log^4x=3/2 (answered by dabanfield)
evaluate... (answered by jim_thompson5910)