SOLUTION: log base 4 (8x-9)-log base 4 (x+1)=1
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Question 744302: log base 4 (8x-9)-log base 4 (x+1)=1
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
= 1
we write this over a single log, subtraction means divide:
= 1
The exponent equiv
=
or just
= 4
multiply both sides by (x+1)
8x - 9 = 4(x + 1)
8x - 9 = 4x + 4
8x - 4x = 4 + 9
4x = 13
x = 13/4
x = 3.25
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