SOLUTION: find the two values of x that satisfy the equation:
2log(base4)X-log(base4)(3X-4))=1/2
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Question 743558: find the two values of x that satisfy the equation:
2log(base4)X-log(base4)(3X-4))=1/2
Found 2 solutions by nerdybill, josmiceli:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
2log(base4)X-log(base4)(3X-4)=1/2
log(base4)X^2-log(base4)(3X-4)=1/2
log(base4)X^2/(3X-4)=1/2
X^2/(3X-4)=4^(1/2)
X^2/(3X-4)=2
X^2=2(3X-4)
X^2=6X-8
X^2-6X+8=0
(X-2)(X-4)=0
X = {2, 4}
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
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The key is to make the substitution
( by inspection )
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Check the answers:
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This is true since
Square both sides
OK
You can check other solution
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