SOLUTION: solve for x log (7x+33)

SOLUTION: solve for x log (7x+33) - log 6 = log (4x-3)

Question 736980: solve for x
log (7x+33) - log 6 = log (4x-3)
Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
log a - log b = log (a/b).

log ((7x+33)/6) = log(4x-3)

raise 10 to the power of both sides of the equation. That will remove the log (base 10). 10 ^ (log((7x+33)/6) = (7x+33)/6. 10^(log(4x-3)) = 4x-3.

(7x+33)/6 = 4x-3

7x+33 = 24x-18

51 = 17x

3=x

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