SOLUTION: Solve for x: log16 base x÷log8 base x =3

Algebra.Com
Question 736022: Solve for x: log16 base x÷log8 base x =3
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Solve for x: log16 base x÷log8 base x =3
--------
logx(16) / logx(8) = 3
-------
logx(16) = 3*logx(8)
---------------
logx(16) - logx(8^3) = 0
---
logx[16/8^3] = 0
---
That implies 16/8^3 = x^0 = 1
That is a contradiction.
------
Cheers,
Stan H.

RELATED QUESTIONS

how do you solve the problem log16 32= x+3 16 is the... (answered by jim_thompson5910)
solve for x,... (answered by Fombitz)
help solve, log16 32- log16... (answered by stanbon)
log16... (answered by Alan3354,jim_thompson5910,stanbon)
solve for x: log2x^3 - logx = log16 - logx (answered by jsmallt9)
solve for x log16(2x + 1) =... (answered by rapaljer)
Logx-log16=log2x + logx Solve for x (answered by josmiceli,Boreal)
log8 x=1/3 (note,base is... (answered by Alan3354)
solve for x. log (base 10)(x+3)=log(base 10) (2x) + log (base 10)... (answered by lwsshak3)