SOLUTION: I am trying to solve a logarithmic equation and have gotten an answer but its not the right one.. the right is 6 but im not sure how to get it. Please help. this is what I have so

Question 732312: I am trying to solve a logarithmic equation and have gotten an answer but its not the right one.. the right is 6 but im not sure how to get it. Please help. this is what I have so far.
log base 4 (x+2) + log base 4 (x-4) = 2
(x+2)+(x-4)=16
2x-2=16
2x=18
x=9
its not the right one so please help.. Thanks!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log base 4 (x+2) + log base 4 (x-4) = 2
(x+2)+(x-4)=16 ********************
-----------------
Adding logs --> multiplication
(x+2)*(x-4)=16

(x-6)*(x+4) = 0
x = -4, x = 6
----------------
x = -4 doesn't work, give the log of a negative number.

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