SOLUTION: if a={{{1003*(2006^2007+1/2006^2007)}}}
b={{{1003*(2006^2007-1/2006^2007)}}}
compute {{{(a^2-b^2)/2006}}}
Algebra.Com
Question 72901: if a=
b=
compute
Answer by rahman(247) (Show Source): You can put this solution on YOUR website!
=
=========================================
a+b=+ =
=
=
=
============================
a-b=-=
=
=
=
============================
====
=2006
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