SOLUTION: y=1/5 log(base3)(9x-36)^(15) - 13 Apply the laws of logarithms to change the form of the equation. Graph the function by first stating the basic function and then describe each tr

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Question 724595: y=1/5 log(base3)(9x-36)^(15) - 13
Apply the laws of logarithms to change the form of the equation. Graph the function by first stating the basic function and then describe each transformation applied in order. Specifically describe what happens to the domain, range, asymptotes, x-intercept, and vertical stretch or compression.
I have a problem with this. What i have tried already:
y= -7 -3log(base3)(x-4)

Found 2 solutions by stanbon, jsmallt9:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
y=1/5 log(base3)(9x-36)^(15) - 13
Apply the laws of logarithms to change the form of the equation.
------
y = log3(9x-36)^3 - 13
--
Graph the function by first stating the basic function and then describe each transformation applied in order. Specifically describe what happens to the domain, range, asymptotes, x-intercept, and vertical stretch or compression.
-----
Before Transformation:
y = log3(x)
Domain: x > 0
Range: All Real Numbers
Asymp: x = 0
x-int: log3(x) = 0
x = 3*0 = 1
-----
stretch or compress: none
------------------------------
After Transformation::
Domain: x > 4
Range: All Real Numbers
Asymp: x = 4
x-int: Let y = 0 ; solve for "x"
(9x-36)^3 = 3^13
9x-36 = 3^(13/3) = 116.82
9x = 152.82
x = 16.98
Stretch: Around 30
---------------------

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cheers,
Stan H.

Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
You've done some good work so far but I believe there is an error:








Unless I've made an error, there should be a +3 in front of the log.

The basic function is and its graph looks like:

We can see that the domain is all positive numbers (x > 0) and that the range is all real numbers. There is a vertical asymptote at x = 0. The x-intercept is (1, 0).

For ...Here's the graph:


P.S. In response to the question in your "thank you"...
As you've suspected the "3" in x-3 causes a right shift of three. Both the domain and the asymptote move to the right by 3. The "2" in -2 causes a vertical stretch by factor of 2. The "-" in -2 causes a reflection in the x-axis. (Think of the graphs above being flipped upside down.) And the -1 is a vertical shift of -1. The range is still all real numbers. To see some y's that are greater than -1, try some x's between 3 and 4.

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