SOLUTION: Suzie owns a car and moped. She can afford 14 gallons of gasoline to be split between the car and the moped. Suzie�s car gets 30 mpg and, with the fuel currently in the tank, can h

Question 724412: Suzie owns a car and moped. She can afford 14 gallons of gasoline to be split between the car and the moped. Suzie�s car gets 30 mpg and, with the fuel currently in the tank, can hold at most an additional 12 gallons of gas. Her moped gets 100 mpg and can hold at most 4 gallons of gas. How many gallons of gasoline should each vehicle use if Susie wants to travel as far as possible? What is the maximum number of miles that she can travel?
can anyone helpme please

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
I've tried to analyze this, and I believe it's a linear optimization problem, but intuition from facts in the problem description makes me think, put in as much gasoline into the moped as it can hold, 4 gallons, and put the remaining 10 gallons into the car. That will give the most mileage possible with the 14 gallon allotment of gasoline.

According to that, miles will be miles.
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