SOLUTION: Can you please solve: Log2*(x-2) + Log2*(x+5)=1

SOLUTION: Can you please solve: Log2(x-2) + Log2(x+5)=1

Question 719527: Can you please solve:
Log2*(x-2) + Log2*(x+5)=1
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Log2*(x-2) + Log2*(x+5)=1
log2[(x-2)(x+5)]=log2(2)
(x-2)(x+5)=2
x^2+3x-10=2
x^2+3x-12=0
solve for x using quadratic formula:
x≈-5.27 (reject, x>0)
or
x≈2.27
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