SOLUTION: how do you do lgarithmic properties to solve an equation
this is what i have
log2x+logx=11
log((2x)x)=11
11
(2x)x=10
2
2x -110=0
Algebra.Com
Question 719220: how do you do lgarithmic properties to solve an equation
this is what i have
log2x+logx=11
log((2x)x)=11
11
(2x)x=10
2
2x -110=0
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log2x+logx=11
log(2x*x)=log(11)
2x^2=11
x^2=11/2
x=√(11/2)≈2.35
RELATED QUESTIONS
Please help me with this problem
This is what i have so far
(((log (2,x)+log(x)=11)))... (answered by Alan3354)
So how would I solve the equation: log2x+logx=11 for x?
I'm stuck on this one,... (answered by lwsshak3)
how do you solve an equation like this 9 - 2x=8x - 11 (answered by scott8148)
how do you solve this equation?
3|2x+11|+10=-35
(answered by Fombitz)
how do you solve the equation -6x + 13 = 2x -... (answered by jim_thompson5910)
log(2+x)-log(x)=log 11 could you help explain how to do... (answered by Earlsdon)
how do I solve this problem?
6x-2x+11=-5
(answered by checkley71)
How do I solve this? Thank you!!... (answered by nerdybill)
Solve the equation |X + 11| = |2X + 5|
Here is what I have tried so far but it is not... (answered by stanbon)