SOLUTION: Find a value for X in he equation 2log10X+3 = log10X+log10 500 i'm assured the second line is {{{ log10x^2 }}} +log10 1000 = log10X+log10 500 How do you get that from abo

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The second line is right. It's good to use the log property log a + log b = log (ab). So, the equation then would be:

<---- Both logs are base 10, and so you can just set whatever you're finding the log of equal to each other:



<--- move 500x to the left

<---- Just by looking at this x=0 or x=1/2. We would throw out the x=0 because you can't find the log of 0. (If you have, for example , that would translate to the exponential form . And there is no such number for x that will make zero.)