SOLUTION: Find a value for X in he equation 2log10X+3 = log10X+log10 500 i'm assured the second line is {{{ log10x^2 }}} +log10 1000 = log10X+log10 500 How do you get that from abo

Question 7157: Find a value for X in he equation
2log10X+3 = log10X+log10 500
i'm assured the second line is
+log10 1000 = log10X+log10 500
How do you get that from above, i tried using my calculator but it kept giving me errors.
Answer by prince_abubu(198) (Show Source): You can put this solution on YOUR website!
The second line is right. It's good to use the log property log a + log b = log (ab). So, the equation then would be:

<---- Both logs are base 10, and so you can just set whatever you're finding the log of equal to each other:

<--- move 500x to the left

<---- Just by looking at this x=0 or x=1/2. We would throw out the x=0 because you can't find the log of 0. (If you have, for example , that would translate to the exponential form . And there is no such number for x that will make zero.)
RELATED QUESTIONS
Solve for x: log10 7 = log10x - log10... (answered by Fombitz)

2 log10x+1=log10... (answered by lwsshak3)

Find the unknown quantity in the given equation. log10 x - 2 log10 3= log10... (answered by MathLover1)

Hello, I need help with a few problems i cant seem to work out for homework.... (answered by AnlytcPhil)

I am unable to solve this problem. Kindly help. Log10(x+y)/3 = 1/2(log10x + log10y)... (answered by longjonsilver)

Log10x+lg4x=2 find value of... (answered by stanbon)

if log10x=-2, what is the value of... (answered by dabanfield)

Solve log10(3x + 2) � 2log10x = 1 � log10(5x �... (answered by lwsshak3)

Find the unknown log10x =... (answered by stanbon)