SOLUTION: Differentiate y=4^(csc^2)x +sqrt(x)*log (base of 3) x I differentiated the 4csc and got ln(4^(csc)^2)x then csc^2x *ln4. How do I do the Sqrt? Wouldnt I do the same t

Algebra.Com
Question 712700: Differentiate
y=4^(csc^2)x +sqrt(x)*log (base of 3) x
I differentiated the 4csc
and got
ln(4^(csc)^2)x
then csc^2x *ln4.
How do I do the Sqrt? Wouldnt I do the same thing with Log (base of 3) x? Change that to ln3/ lnx?

Answer by princessleia(1)   (Show Source): You can put this solution on YOUR website!

RELATED QUESTIONS

How do I write csc 2x in terms of csc x? This is what i've done so far: {{{ csc(2x) =... (answered by Alan3354)
How do i graph the equation... (answered by Fombitz)
Find the solutions of the equation that are in the interval [0, 2π). csc^5 theta =... (answered by Alan3354)
csc^2 x=4... (answered by Alan3354)
Differentiate this function f(x) (x-2) / x^(2) I got: 1/x -2/x^(2) Then: x^(-1)... (answered by josgarithmetic)
Solve the equation for solutions over the interval [0,2pi) cot^2 theta= (-5) +4csc... (answered by lwsshak3)
2 cos x csc x = csc... (answered by lwsshak3)
How would I simplify the equation... (answered by Edwin McCravy)
I need a little help verifying an identity. If you could explain how you got the... (answered by lwsshak3)