SOLUTION: How is log 7x +log 7y -log7z as a single logarithm?
Algebra.Com
Question 708399: How is log 7x +log 7y -log7z as a single logarithm?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the logs is the log of the product and the difference of the logs is the log of the quotient:
\ +\ \log(7y)\ -\ \log(7z)\ =\ \log\left(\frac{7x\cdot 7y}{7z}\right))
Note: You still need to simplify the log argument.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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