SOLUTION: how to arrive at the log of -6.83

SOLUTION: how to arrive at the log of -6.83

Algebra.Com

Question 706157: how to arrive at the log of -6.83
Answer by jsmallt9(3759) (Show Source): You can put this solution on YOUR website!
log(-6.83) does not exist. It is impossible to raise 10, the base of "log", to any power and get a negative result like -6.83.
RELATED QUESTIONS
How to solve log 5 (3x-6)=4? the answer is 631/3 How did they get the answer? (answered by Alan3354)

I am two digit number. I am twice the product of my digits. What number am I? I know... (answered by scott8148)

the problem is to simplify the equation 9^{log(3)20} I am told the answer is 400... (answered by lwsshak3)

How to arrive at the answer to the following problem? 2 divided by the 6th root of 81. (answered by Alan3354)

How many terms of the arithmetic sequence -12,-3,6... Must be added to arrive at a sum of (answered by Fombitz)

Explain how to arrive at the vertex algebraically of the following function 6x^2 + 13x (answered by richwmiller)

My problem is: solve log(x^2+3)=log(x+6) There is no log base, so do I set the ( )= ( (answered by stanbon)

6(3x-1)=24 Please show me the steps to arrive at the correct... (answered by Maths68)

Place <,>, or = between each of the following pairs to make true statements. Please... (answered by stanbon)