SOLUTION: express log(a+b) + log(a-b) as a single logarithm
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Question 701862: express log(a+b) + log(a-b) as a single logarithm
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the logs is the log of the product:
\ +\ \log(a\ -\ b)\ =\ \log\left((a\ +\ b)(a\ -\ b)\right))
You will need to finish the problem by multiplying the two binomials. Hint: The product of a pair of conjugates is the difference of two squares.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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