SOLUTION: how do you condense: ln x - 2 ln (x^2 + 1) + 1/2 ln (3 - x^4)

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Question 698692: how do you condense: ln x - 2 ln (x^2 + 1) + 1/2 ln (3 - x^4)
Found 2 solutions by stanbon, Edwin McCravy:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
ln x - 2 ln (x^2 + 1) + 1/2 ln (3 - x^4)
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ln(x) - ln(x^2+1)^2 + ln(3-x^4)^(1/2)
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= ln[x(3-x^4)^(1/2)/(x^2+1)^2]
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Cheers,
Stan H.
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Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Here it is in a little more detail



Make the coefficients become exponents:



Write the first two terms (the difference of two natural logs) as
the natural log of their quotient:



Write those two terms (the sum of two natural logs) as
the natural log of their product:



Change the  exponent to a square root



and put the square root in the numerator multiplied by the x



Edwin
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