SOLUTION: 2ln(X-3)= ln(X+5) + ln4 I have natural logarithms so think can use the one to one property but don't know what to do with the 2 before the first natural log. 2ln(X-3) = ln4X+

Question 693000: 2ln(X-3)= ln(X+5) + ln4
I have natural logarithms so think can use the one to one property but don't know what to do with the 2 before the first natural log.
2ln(X-3) = ln4X+20
Do I move the 2 to square (X+3)?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

2*ln(x-3) = ln(x+5) + ln(4)

2*ln(x-3) = ln[(x+5)*4]

2*ln(x-3) = ln(4x+20)

ln[(x-3)^2] = ln(4x+20)

(x-3)^2 = 4x+20

x^2 - 6x + 9 = 4x+20

x^2 - 6x + 9 - 4x-20 = 0

x^2 - 10x - 11 = 0

(x-11)(x+1) = 0

I'll let you finish. Make sure to check both possible answers (since only one of these values is truly the answer)

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