SOLUTION: log(x-1)+log(x+1)=Log(x+2)^2

Question 691758: log(x-1)+log(x+1)=Log(x+2)^2
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(x-1)+log(x+1)=Log(x+2)^2
-------
log[(x-1)(x+1)] = log(x+2)^2
---
x^2-1 = (x+2)^2
---
x^2-1 = x^2 + 4x + 4
---
4x = -5
x = -5/4
----
Result: No solution as that solution is extraneous.
Cheers,
Stan H.
RELATED QUESTIONS
log(x-1)+log(x+1)=2 (answered by vleith)

log(x+1)+log(x-2)=1 (answered by Alan3354,josmiceli)

log(1-x)-... (answered by josmiceli,ikleyn)

log (x+7) - log (x-2) =... (answered by ankor@dixie-net.com)

log(x-5)=... (answered by Alan3354)

log(x)=1+log(x-2) (answered by fractalier)

2 log (1-x) = log (x+5) + log... (answered by josgarithmetic)

Log(x+2) - log(x-1) = logx -... (answered by ewatrrr)

log(x-1)^2=log(-5x-1) (answered by stanbon)