SOLUTION: Solve the equation and put the solution in exact form.
log(base 9)(x-4)+ log(base 9)(x-4)=1
This is what I have done.....
log(base 9) (x-4)(x-4)=1
(x-4)(x-4)=9
x^2- 4x -4
Algebra.Com
Question 691275: Solve the equation and put the solution in exact form.
log(base 9)(x-4)+ log(base 9)(x-4)=1
This is what I have done.....
log(base 9) (x-4)(x-4)=1
(x-4)(x-4)=9
x^2- 4x -4x+16
x^2-8x+16=9
x^2-8x+7=0
(x-7)(x-1)
X=7, X=1
Answer (7,1)??? how would I put in exact form???? Is this even correct? Thanks!
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Your answers look right. Now you have to plug them
back into the original equation to verify them
I'll rewrite it slightly
Note that
OK
------
Here you run into trouble. You get
It asks you for the log to the base 9 which
gives you a negative number. There is no real
number that can do this, so
is the only answer
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