SOLUTION: Solve 3^x-1=7
Write 6log4x+log4y as a single logarithm
Solve.
3^2x-1 x 81^2/4
___________ ______ = 9^5x
27^1-x
Algebra.Com
Question 687487: Solve 3^x-1=7
Write 6log4x+log4y as a single logarithm
Solve.
3^2x-1 x 81^2/4
__________________ = 9^5x
27^1-x
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve 3^x-1=7
3^(x-1) = 7
(x-1)*log(3) = log(7)
-----
x*log(3) = log(3)+log(7)
x = log(21)/log(3)
x = 2.77
-------------------------
Write 6log4x+log4y as a single logarithm
6*log4(x) + log4(y)
---
= log4(x^6)+log4(y)
---
= log4[x^6*y]
======================
Solve.
3^2x-1 x 81^2/4
__________________ = 9^5x
27^1-x
--------------
[3^(2x-1)*(3^4)^(2/4)]/(3^3)^(1-x) = (3^2)^5x
-----------------
[(3)^(2x-1)*(3^2)]/3^(3-3x) = 3^10x
-----------------
[3^(2x+1)/3^(3-3x)] = 3^10x
------------------
[3^(5x-2)] = 3^10x
-----
5x-2 = 10x
5x = -2
x = -2/5
===========
Cheers,
Stan H.
=============
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