SOLUTION: log(3x+7)+log(x-2)=1
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Question 686444: log(3x+7)+log(x-2)=1
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
log(3x+7)+log(x-2)=1
log(3x+7)*(x-2)=1
(3x+7)(x-2)=10
3x^2-6x+7x-14-10=0
3x^2+x-24=0
3x^2+9x-8x-24=0
3x(x+3)-8(x+3)=0
(3x-8)(x+3)=0
3x-8=0 OR x=8/3
x=8/3
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