SOLUTION: find the value of x if logx-log(x-1)=log3
Algebra.Com
Question 684907: find the value of x if logx-log(x-1)=log3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find the value of x if logx-log(x-1)=log3
------
log[x/(x-1)] = log3
-----
x/(x-1) = 3
x = 3x-3
2x = 3
x = 3/2
===========
Cheers,
Stan H.
===========
RELATED QUESTIONS
If log{{x+y}/3}=1/2{logx+log Y}, then find the value of... (answered by rothauserc)
find value of x
log(x+3) +... (answered by jsmallt9,Saleye)
Please help me. thanks
1.Solve for x:
log4x+log4(x+4)=9
2. For what value of x (answered by robertb)
if x*x+y*y=7xy, prove... (answered by Edwin McCravy)
Hi, could you please help me with these problems?
1. Evaluate log3 (3^8)
2. Find... (answered by stanbon)
If log(x³+3) - log(x+7) + log2 = logx,find the value of x where the bases are... (answered by Alan3354,math_helper)
logx + log(x+2)=log3 to the nearest... (answered by scott8148)
please help me solve these question. logx=2log3-1/2log25+3log2-log3/5 ,find value of... (answered by stanbon)
given logx+y/log2 = log x-y/log3 = log64/log 0.125
find the values of x and y... (answered by Alan3354)