SOLUTION: Can you help me solve. I'm having problems using the laws. thanks in advance.
Log2t^3-Logt = Log16+Logt
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Question 684196: Can you help me solve. I'm having problems using the laws. thanks in advance.
Log2t^3-Logt = Log16+Logt
Found 2 solutions by lwsshak3, MathTherapy:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Log2t^3-Logt = Log16+Logt
log[2t^3/t]=log[16/t]
2t^3/t=16/t
2t^3=16
t^3=8
t=2
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
Can you help me solve. I'm having problems using the laws. thanks in advance.
Log2t^3-Logt = Log16+Logt
------ Cross-multiplying
OR t = 0 (ignore as log of a number CANNOT = 0)
You can do the check!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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