SOLUTION: log_2(x+5) - log_2(x) = 4
and
2^(3x-2)= 3^(2x-1)
Algebra.Com
Question 683329: log_2(x+5) - log_2(x) = 4
and
2^(3x-2)= 3^(2x-1)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log_2(x+5) - log_2(x) = 4
I think you mean base 2
x+5 = 16x
15x = 5
x = 1/3
===========
and
2^(3x-2)= 3^(2x-1)
(3x-2)*log(2) = (2x-1)*log(3)
etc
RELATED QUESTIONS
log (2-3x) - log x = log... (answered by longjonsilver)
(log[2]3)+(log[2]x)=(log[2]5)+... (answered by Fombitz)
log(3x)= log 5 +... (answered by drk)
Find x if \log_2 x^2 + \log_{1/2} x + 3 \log_4 x = 5.
(answered by ikleyn)
Log 2 (3x-2)- Log 2... (answered by edjones)
Log 2 (3x-2)- Log 2... (answered by lwsshak3)
solve for x 2+4(5)^x=16
Solve for x Log of 7 (5x-1)=2
Log of 2 (1- x) - Log of 2... (answered by stanbon)
log x + log 4 =1 please help with this
log x - log 9 =3
(1/2)^3x... (answered by stanbon)
Log(3x+1)+log(1/2)+log(2x-5)=0 (answered by MathLover1)
Solve the following:
log(7)24−log7(x+5)=log(7)8... (answered by harpazo)