SOLUTION: How to solve Log2(x) - Log2(x+4)=3
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Question 681248: How to solve Log2(x) - Log2(x+4)=3
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The difference of the logs is the log of the product.
\ -\ \log_2(x\,+\,4)\ =\ 3)
\ =\ 3)
Use the definition of the logarithm function:
 \ \ \Rightarrow\ \ b^y = x)
 \ \ \Rightarrow\ \ 2^3 = \frac{x}{x\,+\,4})
But the domain of the log function is restricted to positive reals. Therefore the solution set is empty.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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