SOLUTION: could you please show me how to slove these to find x.
log(x+1)+ log(x-1)=log24
2log(base of 4)x-log(base of 4)(x+3)=1
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Question 679707: could you please show me how to slove these to find x.
log(x+1)+ log(x-1)=log24
2log(base of 4)x-log(base of 4)(x+3)=1
Answer by pmatei(79) (Show Source): You can put this solution on YOUR website!
or
You cannot have negative numbers under logarithm, so the only solution is:
Because of the (x+3) in the denominator of the fractions, x cannot be -3 (we cannot divide by zero).
or
or
Because of the , we cannot accept the solution - no negative numbers under logarithm.
Final solution .
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