SOLUTION: log[5](x + 1) - log[5](x - 1) = 2
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Question 679665: log[5](x + 1) - log[5](x - 1) = 2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
log[5](x + 1) - log[5](x - 1) = 2
log[5](x + 1)/(x - 1) = 2
(x + 1)/(x - 1) = 5^2
(x + 1)/(x - 1) = 25
(x + 1) = 25(x - 1)
x + 1 = 25x - 25
1 = 24x - 25
26 = 24x
26/24 = x
13/12 = x
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