SOLUTION: -6log3(x-3)=-24 so far : log 3 (x-3)^-6=-

Algebra.Com
Question 679000: -6log3(x-3)=-24 so far : log 3 (x-3)^-6=-24 3^-24=(x-3)^-6 this is as far as I can get, do you have any other ideas to answer
Answer by Jolliano(16)   (Show Source): You can put this solution on YOUR website!
Firstly,seperate the -6 from the log. It gives
-6 * log3(x - 3) = -24.
Divide both sides by -6. The equation then becomes
log3(x - 3) = 4.
Therefore,
(x - 3) = 3^4
x - 3 = 81
x = 81 + 3
x = 84

RELATED QUESTIONS

-10 + log3 (n+3) = -10 -2log5 7x=2 -6log3 (x-3) =-24 Log -m +2 =... (answered by Alan3354)
Ok the problem I need help is as follows: log base 3 (x-8) + log base 3 (x-3) -log base (answered by josmiceli)
Solve and check equation for x. x/6 - x/8 = 1 This is what I have, but am not sure (answered by Earlsdon,MathLover1,stanbon)
2x - y = 3 This is what i have so far but it doesn't compute 2y = 4x - 6 2x -... (answered by Alan3354)
x + 1 = 4 6 3 what i have so far is 3(x+1) = 4*6 3x +3=24 (answered by elima)
Can you help me please? Graph x=3(y-1)+6 so far I have x=3(y-1)+6 X= 3y - 3 +... (answered by Alan3354)
write the expression as a single logarithm log(x^2+2x-3)/(x^2-4)-log(x^2+7x+6)/(x+2) (answered by lwsshak3)
F(x)= 3x-2 over x^2+2x-24 - x-3 over x^2-9 So far I have (x+6)(x+4) along with... (answered by rothauserc,stanbon)
Please help solve the following. The instructions read "Solve each system by... (answered by jim_thompson5910)