SOLUTION: how do you solve log base 4 of (x+3)+log base 4 of (x-3)=2
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Question 676059: how do you solve log base 4 of (x+3)+log base 4 of (x-3)=2
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
how do you solve log base 4 of (x+3)+log base 4 of (x-3)=2
log4(x+3)+log4(x-3)=2
log4[(x+3)(x-3)]=2
convert to exponential form: base(4) raised to log of number(2)=number[(x+3)(x-3)]
2^4=(x+3)(x-3)=16
x^2-9=16
x^2=25
x=-5 (reject, (x+3)>0)
x=5
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