SOLUTION: Solve for x: 2log3^(x+7+5)=log4*16

SOLUTION: Solve for x: 2log3^(x+7+5)=log4*16

Algebra.Com

Question 675428: Solve for x:
2log3^(x+7+5)=log4*16
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Solve for x:
2log3^(x+7+5)=log4*16
2log3^(x+12)=log64
log3^(x+12)^2=log64
3^(x+12)^2=64
3^(2x+24)=64
(2x+24)log3=log64
2x+24=log64/log3
2x=(log64/log3-24)
x=(log64/log3-24)/2
x≈-10.1072
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