SOLUTION: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16 Can you help me figure out this problem? I have tried to get help from a tutor. W

Question 675254: Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16
Can you help me figure out this problem? I have tried to get help from a tutor. We worked it out together and we both came up with the same thing that was not an answer choice. I sure would appreciate your help.
Found 2 solutions by ankor@dixie-net.com, MathTherapy:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
2^(8+4x) = 1/16
:
Actually
so we have an equiv equation of:

It the bases are equal, the exponents are equal, so we have:
8 + 4x = -4
4x = -4 - 8
4x = -12
x = -12/4
x = -3
:
:
Check this in your calc: enter 2^(8+4(-3)) results: .0625 which is 1/16
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Using the common or natural log to solve the exponnential equation symboliccally. 2^(8+4x)=1/16
Can you help me figure out this problem? I have tried to get help from a tutor. We worked it out together and we both came up with the same thing that was not an answer choice. I sure would appreciate your help.

Since it's asked to solve using common or natural logs, it'll be done so.

� 2 (2) = 8 + 4x

� 4 = 8 + 4x

4x = - 4 � 8

4x = - 12

, or

Send comments and �thank-yous� to �D� at MathMadEzy@aol.com
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