SOLUTION: graph this function g(x)=log2of(x+1)

Question 674335: graph this function g(x)=log2of(x+1)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!

i appears there's a vertical asymptote at x = -1.
the following table helps show that.

x	y = log(2,x+1)
-2	#NUM!
-1	#NUM!
-0.9999	-16.60964047
-0.9	-3.321928095
-0.8	-2.321928095
-0.7	-1.736965594
-0.6	-1.321928095
-0.5	-1
0	0
1	1
2	1.584962501
3	2
4	2.321928095
5	2.584962501
6	2.807354922
7	3
8	3.169925001
9	3.321928095

you cannot take a log of a negative number of or 0.
that is why the first 2 values in the table are invalid.
that is why the graph stops as just to the right of x -1
log (x+1) will be log(0) when x is equal to -1.

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