SOLUTION: log[10](3m-5)+log[10](m)=log[10](2)
How can i solve this equation ? i tried it so many times and i got 2 , is there anyone that can show their steps, just incase.
Algebra.Com
Question 670373: log[10](3m-5)+log[10](m)=log[10](2)
How can i solve this equation ? i tried it so many times and i got 2 , is there anyone that can show their steps, just incase.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
log[10](3m-5)+log[10](m)=log[10](2)
log[(3m-5)(m)]=log2
(3m-5)(m)=2
3m^2-5m-2=0
(3m+1)(m-2)=0
3m+1=0
m=-1/3 (reject, m>0
m-2=0
m=2
Check:
plug in 2 to the original equation
log[10](3m-5)+log[10](m)=log[10](2)
log[10](6-5)+log[10](2)=log[10](2)
log[10](1)+log[10](2)=log[10](2)
0+log[10](2)=log[10](2)
log[10](2)=log[10](2)
m=2 is the correct ans
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