SOLUTION: cuanto vale x para log(x+3)=log 2 - log (x-2)
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Question 668465: cuanto vale x para log(x+3)=log 2 - log (x-2)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log(x+3)=log 2 - log (x-2)
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log[(x+3) = log[2/(x-2)]
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x+3 = 2/(x-2)
(x-2)(x+3) = 2
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x^2 + x -8 = 0
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x = [-1 +-sqrt(1-4*-8)]/2
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x = [-1 +- sqrt(33)]/2
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x = (-1/2) + sqrt(33)/2
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Cheers,
Stan H.
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