SOLUTION: Solve for x: log(3x+8) - log(x-2) =1

Algebra.Com
Question 667600: Solve for x: log(3x+8) - log(x-2) =1
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!




The difference of the logs is the log of the quotient.



Use the definition of the logarithm function and the convention that an unspecified base is assumed to be base 10.





Solve for

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism


RELATED QUESTIONS

Solve for x:... (answered by venugopalramana,sdmmadam@yahoo.com)
solve for log(3x-1) + log2= log4 +... (answered by lwsshak3)
log(3x+2)- log(3x-2)= log5 solve for x (answered by advanced_Learner)
solve for x: log(x + 9) = 1 - log(x - 8) (answered by MathLover1,lwsshak3)
log(3x^2+8)=1+log(x÷2+1) (answered by Edwin McCravy,MathTherapy)
solve for x: log(x + 2) +... (answered by stanbon)
solve for x log(base 4)(x^2-3x) =... (answered by ewatrrr,Gogonati)
solve for x log(base4)(x^2-3x) =... (answered by josmiceli)
log 3x^2 - log 9x = 2 solve for x... (answered by Fombitz)