SOLUTION: Solve the equation log2(-x)+log2(x+12)=5

Algebra.Com
Question 667316: Solve the equation log2(-x)+log2(x+12)=5
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi,
Solve the equation
log2(-x)+log2(x+12)=5
log2(-x(x+12))=5
2^5 = -x(x+12)
x^2 + 12x + 32 = 0
(x + 8)(x+4) = 0
x = -8 0r x = -4
and
log2(8)+log2(4)= 3 + 2 = 5
log2(4)+log2(8)= 2 + 3 = 5
RELATED QUESTIONS

Solve the logarithmic equation for x. log2 3 + log2 x = log2 5 + log2(x − 2) x = (answered by lwsshak3)
Solve the equation: log2(x+7) +... (answered by stanbon,MathLover1)
solve log2 5 + 3 log2 x=3 (answered by nerdybill)
Solve: Log2(2) +log2(x+3)=5 (answered by stanbon)
log2(x - 6) + log2(x - 4) = log2 x solve the logarithmic equation. and round. (answered by lwsshak3)
Solve the equation. 2 log2(x) − log2(x - 3) = 2 +... (answered by Earlsdon)
solve the simultaneous equation: 1.) log2^x - log2^y =2, log2^(x-2y) =3 (answered by Alex.33,MathTherapy)
Solve the logarithmic equation showing step by step.... (answered by MathLover1,Timnewman)
log2^x = log2^5... (answered by themathtutor2009)