SOLUTION: I am having trouble trying to express this equation in Logarithmic form:
e^(x+2)=0.2
Can you please help me?
Algebra.Com
Question 655985: I am having trouble trying to express this equation in Logarithmic form:
e^(x+2)=0.2
Can you please help me?
Found 2 solutions by Alan3354, MathDazed:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
e^(x+2)=0.2
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Get the log of both sides.
x+2 = ln(0.2)
Answer by MathDazed(34) (Show Source): You can put this solution on YOUR website!
(X+2)ln e = ln 0.2
Ln e = 1
X+2 = ln 0.2
X = ln 0.2 - 2
Then solve for x.
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