SOLUTION: the question asks to solve for x, and i'm stuck on it
{{{9*5^x=17*2^x}}}
Algebra.Com
Question 651269: the question asks to solve for x, and i'm stuck on it
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
solve for x
9*5^x=17*2^x
take log of both sides
log9+xlog5=log17+xlog2
xlog5-xlog2=log17-log9
x(log5-log2)=(log17-log9)
x=(log17-log9)/(log5-log2)
x≈.6941
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