SOLUTION: If log[16]x+log[4]x+log[2]x=7, then x=???
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Question 647299
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If log[16]x+log[4]x+log[2]x=7, then x=???
Answer by
ewatrrr(24785)
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Hi,
log[16]x+log[4]x+log[2]x=7
Note:
&
|Multiplying thru by 28 so as all denominators = 1
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